Q:

Jerry has two part-time jobs, one at a grocery store and one at a sporting goods store. He is paid by the hour at each job. Last week, he worked 10 hours at the grocery store and 12 hours at the sporting goods store and earned a total of $168.00. The week before, he worked 14 hours at the grocery store and 8 hours at the sporting goods store and earned a total of $167.00. (a) Determine how much Jerry earns per hour at the grocery store. Show all your work (b) Next week, Jerry wants to earn at least $184.00. He is scheduled to work 8 hours at the grocery store. Write and solve an inequality to find the minimum number of hours he needs to work at the sporting goods store in order to earn at least $184.00. Show all your work.

Accepted Solution

A:
Answer:The number of working hours in the sporting goods store would be more then 16 hoursStep-by-step explanation:Taking x the amont he is making / hour at the grocery store andy the amont he earns/hour as a salesman at the sporting goods store, then10×x+12×y=16814×x+8×y=1674×(y-x)=1$y=x+25 cents[tex]8 \times x + z \times y \geqslant 184[/tex][tex]8 \times x + z \times (x + 1 \div 4) \geqslant 184[/tex]Seeing that x=165/22 =15/2 then[tex]60 + z \times 31 \div 4 \geqslant 184[/tex][tex]z \geqslant 124 \times 4 \div 31[/tex]The number of hours of work needed to surpass 184$ in earnings has to be no less then 16